Math, asked by choudharyashwini35, 8 months ago

If y = log 750 then y is equal to
(A) 2 log 5 + log 3+1
(C) 2 log 5 + 2 log 2+1
(B) 3+ log 3 - 2 log 2
(D) 2+ log 3 - 2 log 2
please as fast as you can​

Answers

Answered by pulakmath007
7

SOLUTION

TO CHOOSE THE CORRECT OPTION

If y = log 750 then y is equal to

(A) 2 log 5 + log 3+1

(C) 2 log 5 + 2 log 2+1

(B) 3+ log 3 - 2 log 2

(D) 2+ log 3 - 2 log 2

FORMULA TO BE IMPLEMENTED

We are aware of the formula on logarithm that

 \sf{1. \:  log_{a}(a) = 1  \: }

 \sf{2. \:  log_{a}( {b}^{n} )  = n log_{a}(b)  \: }

EVALUATION

Here the base of the logarithm is 10

  \sf{y =  log_{10}(750) }

  \sf{=  log_{10}(3 \times 10 \times 25) }

  \sf{=  log_{10}(3) +  log_{10}(10)  +  log_{10}(25)  }

  \sf{=  log_{10}(3) +  1  +  log_{10}( {5}^{2} )  } \:  \: ( \: by \: formula \: 1 \: )

  \sf{=  log_{10}(3) +  1  +  2log_{10}( 5 )  \:  \:  \: ( \: by \: formula \: 2 )}

 \sf{ = 2 log(5)  +  log(3) + 1 }

FINAL ANSWER

The correct option is

 \sf{(A) \:  \: 2 log(5)  +  log(3)  + 1}

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Answered by nandisrinjoydav
0

Option A

Step-by-step explanation:

Option A id the correct answer

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