Question

If y = log (sec x + tan x), then dy/dx=
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Answer 1

Answer:

$y = log( \sec(x) + \tan(x) ) \\ on \: differeniating, \\ \frac{dy}{dx} = \frac{ \sec(x) \tan(x) + { (\sec(x) )}^{2} }{ \sec(x) + \tan(x) }$