Question

If y=log(sinx),then dy/dx is______If y=log(sinx),then dy/dx is_______​

Answer 1

Answer:

Given that y=log(sinx), we need to find the value of

dx

dy

We know that the derivative of log(x) w.r.t x is

x

1

⟹

dx

dy

=

dx

d

(log(sinx))=

sinx

1

×

dx

d

(sinx)=

sinx

1

×cosx=cotx

Hence,

dx

dy

=cotx

Answer 2

cotx

Step-by-step explanation:

log(sinx)

taking derivative and applying chain rule

calling sinx = t

we take a derivative of log t

so we get it as 1/t and then derivative of sin x which is cos x

so we get it as cosx/t

but t=sinx

so we get answer as cosx/sinx

which is cot x

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