Question

if y=log(x^2+2x+5) find dy/dx​

Answer 1

AnswEr :

Given,

$\sf \: y = log( {x}^{2} + 2x + 5)$

We have to find the derivative of y

Differentiating y with respect to x,

$\longrightarrow \sf \: y' = \dfrac{d \bigg( log( {x}^{2} + 2x + 5) \bigg) }{dx}$

• Derivative of log x is 1/x

Using Chain Rule of Differentiation,

$\longrightarrow \sf \: y' = \dfrac{1}{ {x}^{2} + 2x + 5} \times \dfrac{d( {x}^{2} + 2x + 5)}{dx} \\ \\ \longrightarrow \boxed{ \boxed{\sf \: y' = \dfrac{2x + 2}{ {x}^{2} + 2x + 5 } }}$

Answer 2

Answer:

The derivative of y=log⁡(x^2+2x+5) is dy/dx=_______