if y=log_(x) a , dy/dx =
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a/x
Step-by-step explanation:
y = log (x) . a
differentiate w.r.t x (here w.r.t refers with respect to)
dy/dx = log (x) . d/dx (a) + a . d/dx (log (x)) [using product rule]
dy/dx = log (x) . 0 + 1/x .a
dy/dx = a/x
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