Question

if y log x=x-y then prove dy/dx=log x/(1+log x)^2​

Answer 1

Answer:

y log x=x-y

Y(1+ log x) =x

Y=x/(1+logx) by quotient rule

dy/dx=[(1+log x) 1-x(0+1/x)]/(1+logx)^2

=(1+ logx - 1)/(1+log x) ^2

=log x/(1+logx)^2

Answer 2

Answer:

this answer may help you.thankyou