Question

If y = loga x + logx a + logx x + loga a, then dy/dx​

Answer 1

Step-by-step explanation:

y = loga x + logx a + logx x + loga a

We know loga x = log x/log a

y = log x/log a + log a/log x + log x/log x + log a/log a

y = log x/log a + log a/log x + 1 + 1

y = log x/log a + log a/log x + 2

dy/dx = 1/x log a – [(log a)/(log x)2](1/x)

= 1/x log a – (log a)/x(log x)2