Math, asked by chandanKumar329, 1 year ago

If y = loge x^2 then the value of dy/dx​

Answers

Answered by shwetalahre
1

y = log x^2

dwrt x

dy/dx = d/dx × log x^2

= 2x/x

= 2

Answered by hali29013
3

Answer:

2/x

Step-by-step explanation:

dy/dx =d(logx^2)/dx

= 1/x^2 into 2x

cancle one x with x so ans is

=2/x

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