If y = loge x^2 then the value of dy/dx
Answers
Answered by
1
y = log x^2
dwrt x
dy/dx = d/dx × log x^2
= 2x/x
= 2
Answered by
3
Answer:
2/x
Step-by-step explanation:
dy/dx =d(logx^2)/dx
= 1/x^2 into 2x
cancle one x with x so ans is
=2/x
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