if y = | logex| , find d^2 y/dx^2
Answers
Answered by
0
Answer:
y=log(logx)
Again differentiate both sides w.r.t. x
dx
dy
=
logx
1
dx
d
(logx)
dx
dy
=
logx
1
×
x
1
×1
dx
dy
=
xlogx
1
Again differentiate both sides w.r.t. x
dx
2
d
2
y
=
(xlogx)
2
xlogx(0)−1[logx+x×
x
1
]
dx
2
d
2
y
=
(xlogx)
2
−(1+logx)
Answered by
0
Answer:
Answer is (-1) /x^2
Step-by-step explanation:
dy/dx = 1/x
d^2y/dx^2 = [x * d(1) - 1 * d(x) ] / x^2 = [x * 0 - 1 * 1] / x^2
= -1/(x^2)
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