Question

if y=logtanx find dy/dx

Answer 1

Use chain rule of differentiation

Answer 2

y=log(tan x)

dy/dx = d(log(tanx))/dx

= (1/tanx) *d(sinx/cosx)/dx

= (cosx/sinx) * (cosx/-sinx)

= – (cosx*cosx) / (sinx*sinx)

= – cos2x/sin2x

Hope it helped