If y= logx/x find yn in lebinetz theorem
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Answer: First we need to do a change of base from 10 to e.
log x = ln x / ln 10 = (1 / ln 10) ln x
Then as you start taking derivatives, the (1 / ln 10) will just be a constant.
The first derivative of ln x is 1/x
The second derivative of ln x is -1/(x^2)
The third derivative of ln x is 2 /(x^3)
The fourth derivative of ln x is -6/(x^4)
See the pattern? The derivatives alternate between positive and negative. We will accomplish this with the standard (-1)^(n+1). The value of the coefficient is (n-1)! This is all times (1 / x^n). And do not forget the constant ( 1 / ln 10 )
So the nth derivative of log x is ( 1 / ln 10) ((-1)^(n+1)) (n-1)! (1 / x^n)
Fun!!
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