If y= (logx)^x then dy/dx=?
Answer is log(ex) but how???
Please solve.
brunoconti:
it is not even possible. where did u get the question
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Answered by
3
here u are . . ... ...
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this is TOTALLY wrong!!!!!!!!!
Wrong wrong wrong
Answered by
0
Answer:
y = logx^x
y = xlogx (property of log)
dy/dx = x*1/x + logx*1 (u*v rule)
dy/dx = 1 + logx
dy/dx = loge + logx
dy/dx = log(ex) (property of log)
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