Question

If y= (m^3×n^4)/(16p^2 ) then prove that

3 log m + 4 log n = 4 log 2 + 2 log p + log y

Answer 1

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Answer 2

Step-by-step explanation:

$log \: y = log \: \: {m}^{3} \times {n}^{4} - \: log \: \: {4}^{2} {p}^{2}$

$log \: y \: = \:( log \: m ^{3} ) + (log \: {n}^{4} ) - (log \: {2}^{4} ) - (log \: {p}^{2} )$

$log \: y \: =3 \: log \: m \: + 4 \: log \: n \: - 4 \: log \: 2 \: - \: 2 \: log \: p$