Question

If y-p is a factor of y^6-py^5+y^4-py^3+3y-p-2 find p

Answer 1

Answer:

p = 1

Step-by-step explanation:

Since (y - p) is a factor of the polynomial, putting the value of y = p will result in the polynomial being 0.

$y^6-py^5+y^4-py^3+3y-p-2=0 \ at \ y=p$

$p^6-p^6+p^4-p^4+3p-p-2=0\\2p=2\\p=1$