Question

If y = sec(tan-'x) then dy/dx at x=1


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Answer 1

Answer:

Now, y = sec ( tan-' x)

dy/ dx °?

Step-by-step explanation:

now,

dy/dx = d( sec . tan-' x)/dx

it's done by using uv method -:

Now,

d(u.v)/dx = u dv/dx - v du//dx

now,

d( sec . tan-' x)/dx

= tan-' x . d sec /dx - sec . d tan-' x/dx

= (1/ tanx) ( secx.tanx) - (sec)( 1/ sec^(2) x)

=secx - secx

=0

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