Physics, asked by mishrashruti1788, 8 months ago

if y= sec x × 3/x^1/3 then find dy/dx​

Answers

Answered by shivanikaran
1

Answer:

dy/dx=secx.tanx3/x^1/3+secx(-1/3.3x^2/3)

dy/dx=secx(tan x 3/x^1/3-x^2/3

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