If y=sec x show that, y_(2)=y(2y^2-1)
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Step-by-step explanation:
Given that y = secx
Have to prove that y"= y(2y²–1)
Left hand side,
y = secx
y' = secx.tanx
y" = tanx. secx.tanx + sec².secx
= tan²x.secx + sec³x
= secx ( tan²x+ sec²x)
= secx (2 tan²x +1) [sec²x=tan²+1]
Now,
Right hand side,
y(2y²–1)
=secx( 2sec²x–1)
=secx {2 ( 1 + tan²x) – 1 }
= secx ( 2 tan²x +1)
LHS = RHS
if y = secx then y"= y(2y²–1) (proved)
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