if y = sec(x°+30°) then dy/dx =
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y = 1/cos(x°+30°)
X° can be converted to radians
X°= pi times x÷180
Therefore the derivative is
dy/dx=cos(pi times x ÷180).pi/180
dy/dx= [-1/cos^2 (x°+30°) ](- sin(x°+30°) ) (¶/180)
dy/dx = ¶/180sin(x°+30°)/cos(x°+30°)*cos(x°+30°)
dy/dx = ¶/180 sec(x°+30°).tan(x°+30°)
X° can be converted to radians
X°= pi times x÷180
Therefore the derivative is
dy/dx=cos(pi times x ÷180).pi/180
dy/dx= [-1/cos^2 (x°+30°) ](- sin(x°+30°) ) (¶/180)
dy/dx = ¶/180sin(x°+30°)/cos(x°+30°)*cos(x°+30°)
dy/dx = ¶/180 sec(x°+30°).tan(x°+30°)
Akshataas:
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