If y=secx+tanx.Then prove that dy/dx=ysecx
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Answer: proved that dy/dx = y sec x
Step-by-step explanation:
y = sec x + tan x ----- eq 1
diff. both the side
=> dy/dx = sec x . tan x + sec² x
=> dy/dx = sec x ( tan x + sec x )
substiting the value of sec x + tan x = y in this eq.
=> dy/dx = y sec x
Answered by
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Ans.proved that dy/dx=y sec x
difference both the side
=dt/dx=sec x tan x sec square
dy/dz=sec x (tan x sec x )
subsituting the value sec x+tan x =y
in this equation
=dy/dx=y sec
difference both the side
=dt/dx=sec x tan x sec square
dy/dz=sec x (tan x sec x )
subsituting the value sec x+tan x =y
in this equation
=dy/dx=y sec
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