Question

If y = sin^-1 (2^x) find dy/dx​

Answer 1

Answer:

Step-by-step explanation:

d(sin^-1 x)/dx = 1/$\sqrt{1-x^{2} }$

d(sin^-1 (2^x))/dx = 1/$\sqrt{1-(2^x)^{2} }$ d(2^x)/dx

d(a^x)/dx = a^x lna

d(2^x)/dx = 2^x ln2

d(sin^-1 (2^x))/dx = (2^x ln2)/$\sqrt{1-4x^{2} }$