Question

if y= sin-1 ((cos3x) then Dy/DX is​

Answer 1

Answer:

Let x^3 = y and z=sin^-1(y)

=> y = sin(z)

=> dy/dz = cos(z)

=> dz/dy = 1/cos(z)

=> dz/dy = 1/(1-sin^2(z))^1/2

=> dz/dy = 1/(1-y^2)^1/2

We can substitute z=sin^-1(y)

=> d(sin^-1(y))/dx = 1/(1-y^2)^1/2

Now, we can substitute y=x^3 but remember that as x^3 is also a variable function we must apply chain rule while differentiating.

=> d(sin^-1(x^3)) = [ 1/(1-x^6)^1/2 ] . [ 3x^2 ]

Step-by-step explanation:

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Answer 2

Answer:

answer is -3

Step-by-step explanation:

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