Question

if y=sin^-1(sqrt sin x) then dy/dx=?​

Answer 1

Answer:

Step-by-step explanation:

y=sin^-1(sqrt sin x) then dy/dx=?

diff both sides wrt x

dy/dx=1/$\sqrt{1-\sqrt{sinx{2$ ×d/dx$\sqrt{sinx$

dy/dx=1/$\sqrt{1-sinx$×1/2$\sqrt{sinx$×cosx