Question

If y = sin (2x²+3) find dy/dx
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Answer 1

Answer:

4x*cos(2x²+3)

Step-by-step explanation:

y = sin (2x²+3)

⇒dy/dx = d[sin(2x²+3)]/dx

             = cos(2x²+3)* d(2x²+3)/dx    [ ∵ d(sin x)/dx = cos x]

             = cos(2x²+3)* [2(2x) + 0]   [ ∵d(xⁿ)/dx = n xⁿ⁻¹ and d(constant)/dx=0]

∴dy/dx = 4x*cos(2x²+3)