Math, asked by pratham10710, 8 months ago

If y = sin 3x, find (d²y/dx²)​

Answers

Answered by akhare0207
0

Answer:

9 ( - sin 3x )

Step-by-step explanation:

Differentiating both sides w.r.t. x

dy/dx = d/dx sin 3x

         = cos 3x * d/dx 3x

dy/dx = 3 cos 3x

Differentiating both sides w.r.t. x

d^2y/dx^2 = 3 d/dx cos 3x

                 = 3 ( - sin 3x ) * d/dx 3x

d^2y/dx^2 = 9 ( - sin 3x )

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