Question

if y=sin(axsquare +b) then find out dy/dx

Answer 1

this is ur required result in attachment

Answer 2

Hi...☺

Here is your answer...✌

$y = \sin(a {x}^{2} + b ) \\ \\ using \: chain \: rule \\ \\ \frac{dy}{dx} = \frac{d }{dx} (\sin(a {x}^{2} + b))\\ \\ = \cos(a {x}^{2} + b ) \times \frac{d }{dx} (a {x}^{2} + b) \\ \\ = \cos(a {x}^{2} + b ) \times 2a {x} \\ \\ = 2ax\cos(a {x}^{2} + b )$