Question

If y= sin inverse(x² - 1), then find dy/dx​

Answer 1

Step-by-step explanation:

y= sin inverse(x² - 1),

differenciate with respect to x

dy/dx=d/dx(sin inverse(x² - 1))

=(1/root(1-(x^2-1)^2)) d/dx(x^2-1)

=(1/root(1-x^4-1+2x^2)) (2x)

=(1/root(x^2(2-x^2))) (2x)

= 2x/xroot(2-x^2)

=2/root(2-x^2)