Question

If y=sin (sinx).prove that y"+(tanx)y'+ycos^2 (x)=0.....can we prove this sum by multiplying sin inverse and then differentiating

Answer 1

Y'=cos(sinx). cosx
Y"=-sinx cos(sinx)-sin(sinx). cosx cosx
Y"+tanx cosx cos(sinx)+Y cosx cosx=0
Y"+tanx Y'+Y cosx cosx=0