Question

if y=sin(t^2) then d^2y/dt^2​

Answer 1

Answer:

Explanation:x=sin t and y=cos^2 (t), find d^2y/dx^2

 

dx = cos t dt, dy = -2 cos t sin t dt

 

dy/dx = -2 cost t sin t /cos t = - 2 sin t = - 2 x

 

d^2y/dx^2 = - 2

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