Question

if y=sin theta +√3 cos theta then., calculate maximum value of y​

Answer 1

Given : trigonometric equation is ...

y = sinθ + √3cosθ

To find : The maximum value of y.

solution : y = sinθ + √3cosθ

⇒y = 2 [1/2 sinθ + √3/2 cosθ ]

⇒y = 2[cos60° sinθ + sin60° cosθ ]

we know, cosA sinB + sinA cosB = sin(A + B)

so, cos60° sinθ + sin60° cosθ = sin(θ + 60°)

⇒y = 2sin(θ + 60°)

we know, maximum value of sine function is 1.

so, maximum value of sin(θ + 60°) = 1

so, the maximum value of y = 2 × 1 = 2

Therefore the maximum value of y = 2

also read similar questions : if sec theta = cos^2 theta then find the value of sin^4theta +2sin^3theta +sin^2theta

https://brainly.in/question/6161102

sin^2theta /cos theta +cos theta =sec theta

https://brainly.in/question/15960573

Answer 2

Answer:

just copy the first one cause I don't know the answer but the answer is 2