Question

If y = sin x. and. x= 3t .
then find dy/ dt.
(a).3 cos (x)
(b).cos x
(c).3 cos (3t)
(d).-cos x​

Answer 1

if y = Sin X .....(1)

and X = 3t

put X = 3 t in ...(1)

then y = sin(3t)

now by chain rule find its derivative

then dy/dx = 3 cos (3t)

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Answer 2

Answer:

3 cos(3t)

Explanation:

d/dt (sin (3t))

Using Chain Rule,

(let 3t = a)

d/da (sin (a)) * d/dz (3z)

= cos(a) * 3

= 3 cos(3t)