Question

If y=sin x / log x then find dy/dx

Answer 1

Answer:

$\frac{dy}{dx} = \frac{ \sin(x) \frac{1}{x} - log(x) \cos(x) }{ {( log(x))}^{2} } \\ = > \frac{dy}{dx} = \frac{ \sin(x) }{x {( log(x))}^{2} } - \frac{ \cos(x) }{ log(x) }$

Step-by-step explanation:

we can solve this problem by using u/v rule

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