Question

if y=sinhx/1+sinhx, find dy/dx​

Answer 1

Answer:

$y = \frac{sinhx + 1 - 1}{1 +sinhx} \\ \\ = 1 - \frac{1}{1 + sinhx} \\ \\ now \: diff . using \: chain \: rule\\ \\ \frac{dy}{dx} = 0 - ( - 1) \frac{1}{(1 + sinhx) {}^{ 2} } \frac{d}{dx} (1 + sinhx) \\ \\ = \frac{coshx}{(1 +sinhx) {}^{2} }$