Question

If y = sinx(1+cosx), then dy/dx is

1/(1+sinx)
1/(1+cosx)
(1+sinx)
(1+cosx)​

Answer 1

Answer:

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Answer 2

y=

1+cosx

1−cosx

⇒y=

1+cosx

1−cosx

×

1−cosx

1−cosx

=

1−cos

2

x

1−cosx

=

sinx

1−cosx

=cscx−cotx

∴

dx

dy

=tan(

2

x

)cscx

=

cos

2

x

(2sin(

2

x

)cos(

2

x

))

sin(

2

x

)

=

2

1

sec

2

(

2

x

)