Question

If y=sinx.logx,thendy/Dx=

Answer 1

Applying the u.v rule,
d/dx(sinx). logx + sinx. d/dx(logx) = 
cosx.logx + sinx. x

Answer 2

APPY U.V RULE
WE GET,
y = d/DX (sinx.logx) =
sinx.1/x + logx.cosx
sinx/x + logx.cosx
hence this was the answer...
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