if y=√sinx +siny then find dy /dx
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Answer:
Answer
Given, y=
sinx+y
⟹y
2
=sinx+y
Differentiate w.r.t. x,
2y
dx
dy
=cosx+
dx
dy
dx
dy
=
2y−1
cosx
Answered by
0
Answer:
Step-by-step explanation:
Given, y= sinx+y
⟹y2
=sinx+y
Differentiate w.r.t. x,
⟹2y dx dy
=cosx+ dx dy
⟹ dx dy
= 2y−1 cosx
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