Question

if y=tan^-1(6x-7/6+7x) then dy/DX is​

Answer 1

Step-by-step explanation:

We have,

$y = \tan^{ - 1} ( \frac{6x - 7}{6 + 7x} )$

$y = \tan^{ - 1} ( \frac{x - \frac{7}{6}}{1 + \frac{7}{6} .x} )$

$y = \tan^{ - 1} ( x ) - \tan ^{ - 1} ( \frac{7}{6} )$

Differentiating both sides, w.r.t x,

$\frac{dy}{dx} = \frac{1}{1 + {x}^{2} }$