Question

If y = tan-'( (sin x + cos x), find dy dx?​

Answer 1

Step-by-step explanation:

Given ,

y=tan^-1(sin(x)+cos(x))

dy/dx=d/dx(tan^-1(sin(x)+cos(x)))

= 1/1+(sinx+cosx)^2 x d/dx(sinx+cosx)

= 1/1+(sinx+cosx)^2 x cosx-sinx

= (cosx-sinx)/(sinx+cosx)^2