Physics, asked by vivek1162, 11 months ago

if y=tan x then
(A) dy/dx=sec^2 x
(B) dy/dx= secx tanx
(c) d^2y/dx^2= 2sec^2x tanx
(d) d^2y/dx^2= 2secx tan^2x​

Answers

Answered by ayushijaiswal50
3

Answer:

B

Explanation:

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Answered by mistake00
1

Answer:

(A) sec^2x

Explanation:

If y=tan x, then dy/dx=d(tan x)/ dx is always equal to sec^2x

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