Question

If y=tan x then what is the value of x, dy/dx=1

Answer 1

$= = = = = >$

$y = tanx$

$\frac{dy}{dx} = 1 .......(1)$

Now,

$y = tan \: x$

$\frac{dy}{dx} = \frac{d}{dx} (tanx)$

$\frac{dy}{dx} = { \sec }^{2} x......(2)$

from. (1) and (2)

$= > {sec}^{2}x = 1$

$\sec(x) = \sqrt{1}$

$\sec(x) = 1$

$x = {0}^{0}$

$\boxed{\textbf{\large{x = 0 degree }}}$

Answer 2

Answer:

x = π

Step-by-step explanation:

d/dx (tanx) = sec^2x

sec^2x = 1

sec^2x - 1 = 0

(secx-1)(secx+1) =0

secx = 1 or -1

cosx = 1 or -1

x = nπ

X = π