Question

if y varies as the square of x, and y is 4 when x is 4, find y when x is 3.
(with solution pls)
(direct variation)

Answer 1

Answer:

Y=9/4

Step-by-step explanation:

Y=K(X^2)

Y=4 and X=4

then,

Y=K(X^2)

4=K(4^2)

4=K*16

K= 4/16

K=1/4

now, X=3. and K=1/4

Y=K(X^2)

Y= 1/4*(3^2)

Y=1/4*9

Y=9/4