Question

If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?

Answer 1

HEY BUDDY...!!

HERE'S THE ANSWER..


_________________________

▶️ According to question , x is directly proportional to y i.e

=>
$x \: \infty \: y \\ \\ x \: = \: k y$
▶️ Here k is proportionally constant

=> Now ,

=> y = 6 then x = 72

=> k = x / y__________( 1 )

=> k = 72 / 6

=> k = 12

⏺️ If x = 8 then y = ?

=> by eqn 1

=> y = x / k

=> y = 8 / 12

=> y = 2 / 3



HOPE HELPED


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Answer 2

Hey there!

Given, y varies directly as x.

So, y  ∝ x.

that implies, y = kx

that implies, y/ x = k

Where , K is called proportionality constant.

Given,
If y = 6 , then x = 72 .

So, k = y/x

k = 6 / 72

k = 1/12 ... ( Equation 1 )

Now,
Given
x = 8

We know that,
k = 1/12
k = y/x

So,
$\frac{1}{12 } = \frac{y}{8} \\ 8 \times 1 = y \times 12 \\ y = \frac{8}{12} \\ y = \frac{2}{3}$

Therefore, The value of y is 2/3 if x = 8