Math, asked by jayagedar6535, 29 days ago

If y=(x-1)²(3x+2)⁴ find dy/dx

Answers

Answered by DEBOBROTABHATTACHARY
1

Y= (x-1)²(3x+2)⁴

dY/dx = d/dx {(x-1)²(3x+2)⁴}

= d/dx {(x - 1)^2} . (3x+2)^4 + (x-1)^2 + d/dx {(3x+2)^4}

= 2.(x-1). d/dx{(x-1)} . (3x+2)^4 + (x-1)^2 + 4.(3x+2)^3 . d/dx{(3x+2)}

= 2.(x-1). (1 + 0) . (3x+2)^4 + (x-1)^2 + 4.(3x+2)^3 . (3 +0)

= 2. (x-1) . (3x+2)^4 + (x-1)^2 + 12(3x+2)^3. (ans.)

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