Math, asked by pallaviyadav0150, 4 months ago

if y=(x+1) (x+2)find dy/dx​

Answers

Answered by DashingMango55
4

Answer:

y = (x+1)(x+2)

y = x²+2x+x+2

y = x²+3x+2

Now, dy/dx = 2x+3

Hope it helps you!!

Answered by riddhimajain20
2

Answer:

(3x^2–3x-2)/2.x.√x.

Step-by-step explanation:

y=(x-1)(x-2)/x^1/2. = (x^2-3x+2)/x^1/2

dy/dx=[√x.(2x-3)-1/2√x.(x^2-3x+2)]/(√x)^2

dy/dx =[2x(2x-3)-(x^2-3x+2)]/2x√x.x

dy/dx =[4x^2–6x-x^2+3x-2]/2x√x.

dy/dx=(3x^2–3x-2)/2.x.√x.

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