if y=(x+1) (x+2)find dy/dx
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Answered by
4
Answer:
y = (x+1)(x+2)
y = x²+2x+x+2
y = x²+3x+2
Now, dy/dx = 2x+3
Hope it helps you!!
Answered by
2
Answer:
(3x^2–3x-2)/2.x.√x.
Step-by-step explanation:
y=(x-1)(x-2)/x^1/2. = (x^2-3x+2)/x^1/2
dy/dx=[√x.(2x-3)-1/2√x.(x^2-3x+2)]/(√x)^2
dy/dx =[2x(2x-3)-(x^2-3x+2)]/2x√x.x
dy/dx =[4x^2–6x-x^2+3x-2]/2x√x.
dy/dx=(3x^2–3x-2)/2.x.√x.
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