Question

if y=(√x- 1\√x)² then dy\dx=​

Answer 1

Answer:

d(√x-1\√x)²\dx

We have,

y=

x

+

x

1

On taking differentiating both sides w.r.t x, we get

dx

dy

=

2

x

1

−

2(x)

2

3

1

Since, x=1

Therefore,

dx

dy

∣

∣

∣

∣

∣

x=1

=

2

1

1

−

2(1)

2

3

1

dx

dy

∣

∣

∣

∣

∣

x=1

=

2

1

−

2

1

dx

dy

∣

∣

∣

∣

∣

x=1

=0