If y=x-1/x+3 then x=?
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Given,
x/y + y/x=1
Now,
(x² + y²)/xy=1
=> x² + y²= xy
=> x² + y² — xy=0
=> (x+y)(x² — xy + y²)=0(x+y)
Now, (x + y)(x² — xy + x²)=x³ + y³
=> x³ + y³= 0
Hence,
x³ + y³=0
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