Math, asked by nehadey052, 9 months ago

if y=x^2-5x+7.then find Dy/ dx?

Answers

Answered by Anonymous
2

Given that ,

The function is y = (x)² - 5x + 7

Differentiating with respect to x , we get

 \sf \mapsto \frac{dy}{dx}  =  \frac{d \{ {(x)}^{2} - 5x + 7  \}}{dx} \\  \\  \sf \mapsto  \frac{dy}{dx}  =2x - 5 + 0 \\  \\ \sf \mapsto  \frac{dy}{dx}  =2x - 5

 \sf  \large{ \underline{Remmember :-}}

Power rule :

 \sf \mapsto  \frac{d {(x)}^{n} }{dx}  = n {(x)}^{n - 1}

Constant rule :

 \sf \mapsto  \frac{d(Constant)}{dx}  = 0

Answered by rohit301486
3

Given that ,

The function is y = (x)² - 5x + 7

Differentiating with respect to x ,

\sf \mapsto \frac{dy}{dx} = \frac{d \{ {(x)}^{2} - 5x + 7 \}}{dx}

\sf \mapsto \frac{dy}{dx} =2x - 5 + 0

 \sf \mapsto \frac{dy}{dx} =2x - 5

\sf \large{ \underline{Remmember :-}}

Power rule :

\sf \mapsto \frac{d {(x)}^{n} }{dx} = n {(x)}^{n - 1}

Constant rule :

\sf \mapsto \frac{d(Constant)}{dx} = 0

Similar questions