Math, asked by lucky4669, 8 months ago

If y=x^2 sin (x^3) then integration of y dx=

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Answered by kaiffarooque65

0

Answer:

∫(x2)(sinx3)dx=−13cosx3+ C. Explanation: ∫(x2)(sinx3)dx. Let u=x3 so that du=3x2dx. Out integral becomes

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