if y = x^2
then , dy/dx = ??
and , dy/dt = ??
Anonymous:
wrong
Answers
Answered by
2
y= x²
dy/dx
= y/x
= x²/x
= x
dy/dt
= y/t
= x²/t
dy/dx
= y/x
= x²/x
= x
dy/dt
= y/t
= x²/t
Answered by
2
hii
here is your answer....
y=x^2
dy/dx=dx^2/dx
=2x ( dx^n/dx=nx^n-1)
and dy/dt=dx^2/dx.dx/dt
=2x.dx/dt
=2x.0=0 (the value of dx/dt=0)
I think it will help you then you mark me brainlist please please please ....
here is your answer....
y=x^2
dy/dx=dx^2/dx
=2x ( dx^n/dx=nx^n-1)
and dy/dt=dx^2/dx.dx/dt
=2x.dx/dt
=2x.0=0 (the value of dx/dt=0)
I think it will help you then you mark me brainlist please please please ....
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