Question

if Y=x^3+ 2x + 1 then DY/DX at x=1?​

Answer 1

Answer:

2x^2+2

Explanation:

Answer 2

dy/dx at x = 1 is 5

Given: $y = x^{3} + 2x + 1$

To find: dy/dx at x = 1

Solution:

 We have, $y = x^{3} + 2x +1$

⇒

$\frac{dy}{dx} = 3x^{2} + 2 + 0$

$\frac{dy}{dx} = 3x^{2} + 2$

when dy/dx at x = 1,

$\frac{dy}{dx} = 3*1^{2} + 2$

$\frac{dy}{dx} = 3 + 2$

$\frac{dy}{dx} = 5$

∴ dy/dx at x=1 is 5