if (y/x)^a. (x/y)^c=(x/z)^b and a,b,c are in AP then prove that X,Y,Z are in GP
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Answer:
Given a,b,c are in A.P
⟹2b=a+c
And also x,y,z are in G.P
⟹y=
xz
LHS=x
b−c
.y
c−a
.z
a−b
=x
b−c
.z
a−b
.(
xz
)
c−a
=x
b−c
.z
a−b
.x
2
c−a
.z
2
c−a
=x
2
2b−(a+c)
z
2
2b−(a+c)
=x
0
.z
0
=1
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